The initial speed of the person is 8 m/s. Calculate the angle of jump the person has to take to jump across a height of 2 m. Solved examples for a maximum height of a projectileĪ person is participating in a high-jump competition. The displacement in the y-direction(S) will the maximum height achieved by the projectile.The initial velocity in the y-direction will be u*sinθ.All the 3 equations of motion are valid in a projectile motion.ĭerivation for the formula for a maximum height of projectile motion Derivation for the formula of maximum height of a projectile.At the point of maximum height, the vertical component of velocity becomes zero.

The only force acting on the object in the projectile motion is the force of gravity with an acceleration of gravity g = ~9.8 m/s on Earth.There are some points to be kept in mind while discussing the maximum height of a projectile motion. For more examples of projectile motion, you can read our article on 20 examples of projectile motion. This becomes important in sports like javelin throw, high jump, pole vault, etc. This calculation is also important in the design of weapons like rockets, slingshots bows, and arrows, etc. So, we have to balance the initial speed and the maximum height in order to obtain the desired distance or range. But, for obtaining a certain amount of distance a certain maximum height is also necessary for the given initial speed. We are generally concerned about the distance covered by the object. When any object is thrown, it follows a parabolic path. Why is the maximum height of a projectile important?

Range of projectile